(2x+3)^2+8(2x+3)+11=0

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Solution for (2x+3)^2+8(2x+3)+11=0 equation: 



(2x+3)^2+8(2x+3)+11=0

We multiply parentheses

(2x+3)^2+16x+24+11=0

We add all the numbers together, and all the variables

16x+(2x+3)^2+35=0

We move all terms containing x to the left, all other terms to the right

16x+(2x+3)^2=-35

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